Java8 Collections.sort()及Arrays.sort()中Lambda表达式及增强版Comparator的使用
生活随笔
收集整理的這篇文章主要介紹了
Java8 Collections.sort()及Arrays.sort()中Lambda表达式及增强版Comparator的使用
小編覺得挺不錯的,現在分享給大家,幫大家做個參考.
摘要:本文主要介紹Java8 中Arrays.sort()及Collections.sort()中Lambda表達式及增強版Comparator的使用。
?
不廢話直接上代碼
import com.google.common.collect.Lists; import org.junit.Assert; import org.junit.Test; import java.util.Arrays; import java.util.Collections; import java.util.Comparator; import java.util.List;public class ComparatorTest {@Testpublic void test1(){/*** Collections.sort()使用*///被排序的集合List<User> userList = Lists.newArrayList(new User("Jack",11),new User("Jack",10));//1. Java8之前,使用匿名內部類的基本排序Collections.sort(userList, new Comparator<User>() {@Overridepublic int compare(User user1, User user2) {return user1.getAge().compareTo(user2.getAge());}});//2. Java8,使用Lambda表達式的基本排序 Collections.sort(userList,(User user1, User user2) ->user1.getAge().compareTo(user2.getAge()));//userList.sort((User user1, User user2) -> user1.getAge().compareTo(user2.getAge()));//3. Java8,Lambda表達式可以簡化,省略定義類型UseruserList.sort((user1, user2) -> user1.getAge().compareTo(user2.getAge()));//4. Java8,Lambda表達式,多條件排序userList.sort((user1, user2) -> {if (user1.getName().equals(user2.getName())) {return user1.getAge() - user2.getAge();} else {return user1.getName().compareTo(user2.getName());}});//5. Java8,多條件組合排序 userList.sort(Comparator.comparing(User::getName).thenComparing(User::getAge));//6. Java8,提取Comparator進行排序 Collections.sort(userList, Comparator.comparing(User::getName));//7. Java8,自定義靜態的比較方法來排序(靜態方法必須寫在被比較的類(這里是User類)中) userList.sort(User::compareByAgeThenName);//8. Java8,反轉排序Comparator<User> comparator = (user1, user2) -> user1.getName().compareTo(user2.getName());userList.sort(comparator);//先按name排序userList.sort(comparator.reversed());//反轉排序Assert.assertEquals(userList.get(0),new User("Jack",10));/*** Arrays.sort()使用*///被排序的字符串數組String[] months = {"January","February","March","April","May","June","July","August","September","October","December"};//按字符串長度排序//1.Arrays.sort(months, (a, b) -> Integer.signum(a.length() - b.length()));//2. Arrays.sort(months, Comparator.comparingInt(String::length));//3.Arrays.sort(months, (a, b) -> a.length() - b.length());//4. Arrays.sort(months,(String a, String b) -> { return Integer.signum(a.length() - b.length()); });System.out.println(Arrays.toString(months));} }?
原文地址:https://blog.csdn.net/qq_27127145/article/details/83930498
轉載于:https://www.cnblogs.com/huiyi0521/p/10990535.html
總結
以上是生活随笔為你收集整理的Java8 Collections.sort()及Arrays.sort()中Lambda表达式及增强版Comparator的使用的全部內容,希望文章能夠幫你解決所遇到的問題。
- 上一篇: Leetcode 53 最大子串和
- 下一篇: Class NPOI