指针的加减法计算
#include<stdio.h>
int?main()
{
int?arr[10]={1,2,3,4,5,6};
int?*p?=?arr;
p++;
printf("%d?%d\n",arr[0],arr[1]);
return?0;
}
?
(2)?指針加數(shù)字:指針加法需要調(diào)整,調(diào)整的權(quán)重為指針去掉一個(gè)*號(hào),求sizeof。
例:#include<stdio.h>
int?main()
{
int?*p?=?(int*)1000;
printf("%d\n",(char??***)p+2);//1008
printf("%d\n",(short?*)p+2);//1004
printf("%d\n",(double?**)p+2);//1008
printf("%d\n",(unsigned?long?*)p+2);//1008
printf("%d\n",(char??*)p+2);//1002
printf("%d\n",(unsigned?long?long?)p+2);//1002//這里的unsigned?long?long是指強(qiáng)轉(zhuǎn)指針的類型
return?0;
}?
(3)指針+指針 ?(非法,無意義)
(4)指針-數(shù)字:需要調(diào)整,調(diào)整的權(quán)重位sizeof指針去掉一個(gè)*
注:和指針+數(shù)字算法相同
#include<stdio.h>
int main()
{
int *p = (int *)0x2010;//注意是十六進(jìn)制
printf("%x\n",p-2);//2008
printf("%x\n",(float *)p-2);//2008
printf("%x\n",(double *)p-2);//2000
printf("%x\n",(short *)p-2);//200c
printf("%x\n",(unsigned long *)p-2);//2008
printf("%x\n",(long *)p-2);//2008
printf("%x\n",(long long)p-2);//200e
printf("%x\n",(char *)p-2);//200e
return 0;
}
(5)指針-指針:間隔的單元個(gè)數(shù),需要調(diào)整,調(diào)整的權(quán)重位sizeof(指針去掉一個(gè)*)
注:指針-指針的計(jì)算:1、計(jì)算間隔的字節(jié)數(shù),2、除以權(quán)重
#include<stdio.h>
int main()
{
int arr[10] = {0};
int *p = &arr[1];//x+4
int *q = &arr[7];//x+28
printf("%d\n",p-q);//-6
printf("%d\n",q-p);//6
printf("%d\n",(short *)q-(short *)p);//12
printf("%d\n",(long long*)q-(long long *)p);//3
printf("%d\n",(double *)q-(double *)p);//3
printf("%d\n",(unsigned long)q-(unsigned long)p);//24
printf("%d\n",(char **)q-(char **)p);//6
return 0;
}
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