最簡單的解決方案可能是創(chuàng)建一個函數(shù),該函數(shù)將顯示的消息作為輸入,并在測試其滿足條件后返回用戶輸入：

def guess_input(input_message):

flag = False

#endless loop until we are satisfied with the input

while True:

#asking for user input

guess = input(input_message)

#testing, if input was x or exit no matter if upper or lower case

if guess.lower() == "x" or guess.lower() == "exit":

#return string "x" as a sign that the user wants to quit

return "x"

#try to convert the input into a number

try:

guess = int(guess)

#it was a number, but not between 1 and 9

if guess > 9 or guess < 1:

#flag showing an illegal input

flag = True

else:

#yes input as expected a number, break out of while loop

break

except:

#input is not an integer number

flag = True

#not the input, we would like to see

if flag:

#give feedback

print("Sorry, I didn't get that.")

#and change the message displayed during the input routine

input_message = "I can only accept numbers from 1 to 9 (or X for eXit): "

continue

#give back the guessed number

return guess

您可以從主程序中調(diào)用此命令,例如

#the first guess

guess = guess_input("Guess a number from 1 to 9: ")

要么

#giving feedback from previous input and asking for the next guess

guess = guess_input("Too high! Guess again (or X to eXit): ")

總結(jié)

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