#include<iostream> #include<string> using namespace std;//1、值傳遞 void mySwap01(int a, int b) {int temp = a;a = b;b = temp;cout << "mySwap01 a=" << a << endl;cout << "mySwap01 b=" << b << endl;}//2、地址傳遞 void mySwap02(int * a, int * b) {int temp = *a;*a = *b;*b = temp;cout << "mySwap01 a=" << *a << endl;cout << "mySwap01 b=" << *b << endl;}//3、引用傳遞 void mySwap03(int &a,int &b) {int temp = a;a = b;b = temp;cout << "mySwap03 a=" << a << endl;cout << "mySwap03 b=" << b << endl; }int main() {int a = 10;int b = 20;mySwap01(a,b); //值傳遞，形參不會修飾實參// mySwap02(&a, &b);// mySwap03(a, b);cout << "a="<<a<<endl;cout << "b="<<b<<endl;system("pause" ) ;}

值傳遞實參不會改變?

地址傳遞會改變實參的值?

?引用傳遞

總結

以上是生活随笔為你收集整理的C++ 函数的引用传递的全部內容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯，歡迎將生活随笔推薦給好友。