題目描述

【問(wèn)題描述】 下圖給出了一個(gè)迷宮的平面圖，其中標(biāo)記為 1 的為障礙，標(biāo)記為 0 的為可以通行的地方。 010000 000100 001001 110000 迷宮的入口為左上角，出口為右下角，在迷宮中，只能從一個(gè)位置走到這個(gè)它的上、下、左、右四個(gè)方向之一。 對(duì)于上面的迷宮，從入口開(kāi)始，可以按DRRURRDDDR 的順序通過(guò)迷宮，一共 10 步。其中 D、U、L、R 分別表示向下、向上、向左、向右走。 對(duì)于下面這個(gè)更復(fù)雜的迷宮（30 行 50 列），請(qǐng)找出一種通過(guò)迷宮的方式，其使用的步數(shù)最少，在步數(shù)最少的前提下，請(qǐng)找出字典序最小的一個(gè)作為答案。請(qǐng)注意在字典序中D<L<R<U。（如果你把以下文字復(fù)制到文本文件中，請(qǐng)務(wù)必檢查復(fù)制的內(nèi)容是否與文檔中的一致。再試題目錄下有一個(gè) maze.txt，內(nèi)容與下面的文本相同） 01010101001011001001010110010110100100001000101010 00001000100000101010010000100000001001100110100101 01111011010010001000001101001011100011000000010000 01000000001010100011010000101000001010101011001011 00011111000000101000010010100010100000101100000000 11001000110101000010101100011010011010101011110111 00011011010101001001001010000001000101001110000000 10100000101000100110101010111110011000010000111010 00111000001010100001100010000001000101001100001001 11000110100001110010001001010101010101010001101000 00010000100100000101001010101110100010101010000101 11100100101001001000010000010101010100100100010100 00000010000000101011001111010001100000101010100011 10101010011100001000011000010110011110110100001000 10101010100001101010100101000010100000111011101001 10000000101100010000101100101101001011100000000100 10101001000000010100100001000100000100011110101001 00101001010101101001010100011010101101110000110101 11001010000100001100000010100101000001000111000010 00001000110000110101101000000100101001001000011101 10100101000101000000001110110010110101101010100001 00101000010000110101010000100010001001000100010101 10100001000110010001000010101001010101011111010010 00000100101000000110010100101001000001000000000010 11010000001001110111001001000011101001011011101000 00000110100010001000100000001000011101000000110011 10101000101000100010001111100010101001010000001000 10000010100101001010110000000100101010001011101000 00111100001000010000000110111000000001000000001011 10000001100111010111010001000110111010101101111000 【答案提交】 這是一道結(jié)果填空的題，你只需要算出結(jié)果后提交即可。本題的結(jié)果為一個(gè)字符串，包含四種字母 D、U、L、R，在提交答案時(shí)只填寫(xiě)這個(gè)字符串，填寫(xiě)多余的內(nèi)容將無(wú)法得分。

思路分析

bfs

代碼實(shí)現(xiàn)

package lanqiao;import java.util.*; public class Main{static int counts=0;static String s="01010101001011001001010110010110100100001000101010"+ "00001000100000101010010000100000001001100110100101"+ "01111011010010001000001101001011100011000000010000"+ "01000000001010100011010000101000001010101011001011"+ "00011111000000101000010010100010100000101100000000"+ "11001000110101000010101100011010011010101011110111"+ "00011011010101001001001010000001000101001110000000"+ "10100000101000100110101010111110011000010000111010"+ "00111000001010100001100010000001000101001100001001"+ "11000110100001110010001001010101010101010001101000"+ "00010000100100000101001010101110100010101010000101"+ "11100100101001001000010000010101010100100100010100"+ "00000010000000101011001111010001100000101010100011"+ "10101010011100001000011000010110011110110100001000"+ "10101010100001101010100101000010100000111011101001"+ "10000000101100010000101100101101001011100000000100"+ "10101001000000010100100001000100000100011110101001"+ "00101001010101101001010100011010101101110000110101"+ "11001010000100001100000010100101000001000111000010"+ "00001000110000110101101000000100101001001000011101"+ "10100101000101000000001110110010110101101010100001"+ "00101000010000110101010000100010001001000100010101"+ "10100001000110010001000010101001010101011111010010"+ "00000100101000000110010100101001000001000000000010"+ "11010000001001110111001001000011101001011011101000"+ "00000110100010001000100000001000011101000000110011"+ "10101000101000100010001111100010101001010000001000"+ "10000010100101001010110000000100101010001011101000"+ "00111100001000010000000110111000000001000000001011"+ "10000001100111010111010001000110111010101101111000";static Set<String>set=new HashSet<>();public static void main(String[] args) {char [][]map = new char [30][50];boolean[][]vis = new boolean[30][50];for(int i=0;i<30;i++) {for(int j=0;j<50;j++) {map[i][j]=s.charAt(i*50+j);}}Position start=new Position(0,0,0,"");LinkedList<Position>queue=new LinkedList<>();queue.add(start);while(!queue.isEmpty()) {Position now = queue.poll();int i=now.i;int j=now.j;int step=now.step;String route=now.route;if(i==29&&j==49) {System.out.println(route);System.out.println(route.length());}//D 向下走if(i+1<30&&!vis[i+1][j]&&map[i+1][j]=='0') {queue.add(new Position(i+1,j,step+1,route+"D"));vis[i+1][j]=true;//標(biāo)記為走過(guò)的路}//L 向左走if(j-1>=0&&!vis[i][j-1]&&map[i][j-1]=='0') {queue.add(new Position(i,j-1,step+1,route+"L"));vis[i][j-1]=true;//標(biāo)記為走過(guò)的路}//R 向右走if(j+1<50&&!vis[i][j+1]&&map[i][j+1]=='0') {queue.add(new Position(i,j+1,step+1,route+"R"));vis[i][j+1]=true;//標(biāo)記為走過(guò)的路}//U 向上走if(i-1>=0&&!vis[i-1][j]&&map[i-1][j]=='0') {queue.add(new Position(i-1,j,step+1,route+"U"));vis[i-1][j]=true;//標(biāo)記為走過(guò)的路}}} } class Position{public int j;public int i;public int step;public String route;Position(int i,int j,int step,String route){this.i=i;this.j=j;this.step=step;this.route=route;} }

答案

創(chuàng)作挑戰(zhàn)賽新人創(chuàng)作獎(jiǎng)勵(lì)來(lái)咯，堅(jiān)持創(chuàng)作打卡瓜分現(xiàn)金大獎(jiǎng)

總結(jié)

以上是生活随笔為你收集整理的2019蓝桥杯省赛---java---A---4(迷宫)的全部?jī)?nèi)容，希望文章能夠幫你解決所遇到的問(wèn)題。

如果覺(jué)得生活随笔網(wǎng)站內(nèi)容還不錯(cuò)，歡迎將生活随笔推薦給好友。